Base | Representation |
---|---|
bin | 1101000110011011100111… |
… | …0101011000111101011001 |
3 | 1220000000121111111211211222 |
4 | 3101212321311120331121 |
5 | 3341444141114434223 |
6 | 50345101052501425 |
7 | 3014444044260155 |
oct | 321467165307531 |
9 | 56000544454758 |
10 | 14404143124313 |
11 | 4653843307668 |
12 | 174775247a875 |
13 | 8063c6a46127 |
14 | 37b2429a0065 |
15 | 19ea413de0c8 |
hex | d19b9d58f59 |
14404143124313 has 2 divisors, whose sum is σ = 14404143124314. Its totient is φ = 14404143124312.
The previous prime is 14404143124309. The next prime is 14404143124333. The reversal of 14404143124313 is 31342134140441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13251725845264 + 1152417279049 = 3640292^2 + 1073507^2 .
It is a cyclic number.
It is not a de Polignac number, because 14404143124313 - 22 = 14404143124309 is a prime.
It is not a weakly prime, because it can be changed into another prime (14404143124333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7202071562156 + 7202071562157.
It is an arithmetic number, because the mean of its divisors is an integer number (7202071562157).
Almost surely, 214404143124313 is an apocalyptic number.
It is an amenable number.
14404143124313 is a deficient number, since it is larger than the sum of its proper divisors (1).
14404143124313 is an equidigital number, since it uses as much as digits as its factorization.
14404143124313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 14404143124313 its reverse (31342134140441), we get a palindrome (45746277264754).
The spelling of 14404143124313 in words is "fourteen trillion, four hundred four billion, one hundred forty-three million, one hundred twenty-four thousand, three hundred thirteen".
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