Base | Representation |
---|---|
bin | 10100111101100001101… |
… | …101011101101011010011 |
3 | 12002201001200010000012121 |
4 | 110331201231131223103 |
5 | 142100022024232042 |
6 | 3021422442235111 |
7 | 206032530321145 |
oct | 24754155355323 |
9 | 5081050100177 |
10 | 1440453352147 |
11 | 505990401527 |
12 | 1b3204ab5a97 |
13 | a5aac88ab34 |
14 | 4da0b0a8c95 |
15 | 27709848367 |
hex | 14f61b5dad3 |
1440453352147 has 2 divisors, whose sum is σ = 1440453352148. Its totient is φ = 1440453352146.
The previous prime is 1440453352109. The next prime is 1440453352157. The reversal of 1440453352147 is 7412533540441.
It is a strong prime.
It is an emirp because it is prime and its reverse (7412533540441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1440453352147 - 219 = 1440452827859 is a prime.
It is a super-3 number, since 3×14404533521473 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1440453352157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720226676073 + 720226676074.
It is an arithmetic number, because the mean of its divisors is an integer number (720226676074).
Almost surely, 21440453352147 is an apocalyptic number.
1440453352147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440453352147 is an equidigital number, since it uses as much as digits as its factorization.
1440453352147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 43.
Adding to 1440453352147 its reverse (7412533540441), we get a palindrome (8852986892588).
The spelling of 1440453352147 in words is "one trillion, four hundred forty billion, four hundred fifty-three million, three hundred fifty-two thousand, one hundred forty-seven".
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