Base | Representation |
---|---|
bin | 1101000110011110011110… |
… | …0101011110100101000011 |
3 | 1220000002120222211222112221 |
4 | 3101213213211132211003 |
5 | 3342002224120024323 |
6 | 50345305152431511 |
7 | 3014502054510502 |
oct | 321474745364503 |
9 | 56002528758487 |
10 | 14404910704963 |
11 | 46540a7615339 |
12 | 1747927548597 |
13 | 8064b9a87a6c |
14 | 37b2b68ca839 |
15 | 19ea889b055d |
hex | d19e795e943 |
14404910704963 has 2 divisors, whose sum is σ = 14404910704964. Its totient is φ = 14404910704962.
The previous prime is 14404910704949. The next prime is 14404910704969. The reversal of 14404910704963 is 36940701940441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14404910704963 - 233 = 14396320770371 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14404910704963.
It is not a weakly prime, because it can be changed into another prime (14404910704969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7202455352481 + 7202455352482.
It is an arithmetic number, because the mean of its divisors is an integer number (7202455352482).
Almost surely, 214404910704963 is an apocalyptic number.
14404910704963 is a deficient number, since it is larger than the sum of its proper divisors (1).
14404910704963 is an equidigital number, since it uses as much as digits as its factorization.
14404910704963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 52.
The spelling of 14404910704963 in words is "fourteen trillion, four hundred four billion, nine hundred ten million, seven hundred four thousand, nine hundred sixty-three".
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