Base | Representation |
---|---|
bin | 1101000110100000011000… |
… | …0000111111011110111111 |
3 | 1220000010220120111112212220 |
4 | 3101220012000333132333 |
5 | 3342004300313442421 |
6 | 50345431551100423 |
7 | 3014520524106615 |
oct | 321500600773677 |
9 | 56003816445786 |
10 | 14405421234111 |
11 | 4654339813456 |
12 | 1747a4a511713 |
13 | 80656b78850b |
14 | 37b3246236b5 |
15 | 19eab87083c6 |
hex | d1a0603f7bf |
14405421234111 has 32 divisors (see below), whose sum is σ = 19541639406528. Its totient is φ = 9437841638400.
The previous prime is 14405421234103. The next prime is 14405421234133. The reversal of 14405421234111 is 11143212450441.
It is not a de Polignac number, because 14405421234111 - 23 = 14405421234103 is a prime.
It is a super-3 number, since 3×144054212341113 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14405421234811) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 379100965 + ... + 379138961.
It is an arithmetic number, because the mean of its divisors is an integer number (610676231454).
Almost surely, 214405421234111 is an apocalyptic number.
14405421234111 is a deficient number, since it is larger than the sum of its proper divisors (5136218172417).
14405421234111 is a wasteful number, since it uses less digits than its factorization.
14405421234111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47371.
The product of its (nonzero) digits is 15360, while the sum is 33.
Adding to 14405421234111 its reverse (11143212450441), we get a palindrome (25548633684552).
The spelling of 14405421234111 in words is "fourteen trillion, four hundred five billion, four hundred twenty-one million, two hundred thirty-four thousand, one hundred eleven".
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