Base | Representation |
---|---|
bin | 10100111101110100010… |
… | …000010000100000100011 |
3 | 12002201212100112002020221 |
4 | 110331310100100200203 |
5 | 142101141200310024 |
6 | 3021513354343511 |
7 | 206043325605241 |
oct | 24756420204043 |
9 | 5081770462227 |
10 | 1440764463139 |
11 | 50602aa84851 |
12 | 1b329112ab97 |
13 | a5b2c179091 |
14 | 4da3a531791 |
15 | 27726cee3e4 |
hex | 14f74410823 |
1440764463139 has 2 divisors, whose sum is σ = 1440764463140. Its totient is φ = 1440764463138.
The previous prime is 1440764463097. The next prime is 1440764463169. The reversal of 1440764463139 is 9313644670441.
It is a strong prime.
It is an emirp because it is prime and its reverse (9313644670441) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1440764463139 is a prime.
It is a super-3 number, since 3×14407644631393 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1440764463169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720382231569 + 720382231570.
It is an arithmetic number, because the mean of its divisors is an integer number (720382231570).
Almost surely, 21440764463139 is an apocalyptic number.
1440764463139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440764463139 is an equidigital number, since it uses as much as digits as its factorization.
1440764463139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5225472, while the sum is 52.
The spelling of 1440764463139 in words is "one trillion, four hundred forty billion, seven hundred sixty-four million, four hundred sixty-three thousand, one hundred thirty-nine".
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