Search a number
-
+
144091481377 is a prime number
BaseRepresentation
bin1000011000110010000…
…1011000010100100001
3111202220222112200001111
42012030201120110201
54330044404401002
6150110020303321
713260502245304
oct2061441302441
9452828480044
10144091481377
1156121980708
1223b13b41b41
13107844339ac
146d8cb96b3b
153b350173d7
hex218c858521

144091481377 has 2 divisors, whose sum is σ = 144091481378. Its totient is φ = 144091481376.

The previous prime is 144091481327. The next prime is 144091481423. The reversal of 144091481377 is 773184190441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123572637841 + 20518843536 = 351529^2 + 143244^2 .

It is a cyclic number.

It is not a de Polignac number, because 144091481377 - 219 = 144090957089 is a prime.

It is a super-2 number, since 2×1440914813772 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 144091481377.

It is not a weakly prime, because it can be changed into another prime (144091481327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72045740688 + 72045740689.

It is an arithmetic number, because the mean of its divisors is an integer number (72045740689).

Almost surely, 2144091481377 is an apocalyptic number.

It is an amenable number.

144091481377 is a deficient number, since it is larger than the sum of its proper divisors (1).

144091481377 is an equidigital number, since it uses as much as digits as its factorization.

144091481377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 677376, while the sum is 49.

The spelling of 144091481377 in words is "one hundred forty-four billion, ninety-one million, four hundred eighty-one thousand, three hundred seventy-seven".