Base | Representation |
---|---|
bin | 1101000110110101001101… |
… | …0011111001110001001011 |
3 | 1220000200100021101220121211 |
4 | 3101231103103321301023 |
5 | 3342102223312114423 |
6 | 50352154502113551 |
7 | 3015106223266033 |
oct | 321552323716113 |
9 | 56020307356554 |
10 | 14411013004363 |
11 | 4656749168188 |
12 | 1748b4b11b8b7 |
13 | 806c500c0b01 |
14 | 37b6d51288c3 |
15 | 19ece45a410d |
hex | d1b534f9c4b |
14411013004363 has 2 divisors, whose sum is σ = 14411013004364. Its totient is φ = 14411013004362.
The previous prime is 14411013004301. The next prime is 14411013004391. The reversal of 14411013004363 is 36340031011441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14411013004363 is a prime.
It is not a weakly prime, because it can be changed into another prime (14411013004393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205506502181 + 7205506502182.
It is an arithmetic number, because the mean of its divisors is an integer number (7205506502182).
Almost surely, 214411013004363 is an apocalyptic number.
14411013004363 is a deficient number, since it is larger than the sum of its proper divisors (1).
14411013004363 is an equidigital number, since it uses as much as digits as its factorization.
14411013004363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
The spelling of 14411013004363 in words is "fourteen trillion, four hundred eleven billion, thirteen million, four thousand, three hundred sixty-three".
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