Base | Representation |
---|---|
bin | 10100111110001000011… |
… | …011011000100111010001 |
3 | 12002202201221101200121022 |
4 | 110332020123120213101 |
5 | 142102334322033431 |
6 | 3022011125005225 |
7 | 206054605513301 |
oct | 24761033304721 |
9 | 5082657350538 |
10 | 1441102924241 |
11 | 506194038672 |
12 | 1b3366553815 |
13 | a5b84322116 |
14 | 4da6d477601 |
15 | 277468a907b |
hex | 14f886d89d1 |
1441102924241 has 2 divisors, whose sum is σ = 1441102924242. Its totient is φ = 1441102924240.
The previous prime is 1441102924201. The next prime is 1441102924249. The reversal of 1441102924241 is 1424292011441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1208909046016 + 232193878225 = 1099504^2 + 481865^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1441102924241 is a prime.
It is a super-2 number, since 2×14411029242412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1441102924249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720551462120 + 720551462121.
It is an arithmetic number, because the mean of its divisors is an integer number (720551462121).
Almost surely, 21441102924241 is an apocalyptic number.
It is an amenable number.
1441102924241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1441102924241 is an equidigital number, since it uses as much as digits as its factorization.
1441102924241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 35.
Adding to 1441102924241 its reverse (1424292011441), we get a palindrome (2865394935682).
The spelling of 1441102924241 in words is "one trillion, four hundred forty-one billion, one hundred two million, nine hundred twenty-four thousand, two hundred forty-one".
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