Base | Representation |
---|---|
bin | 1101000110110110001000… |
… | …1101100010011011100011 |
3 | 1220000200222200210201010201 |
4 | 3101231202031202123203 |
5 | 3342103231311303042 |
6 | 50352235352210031 |
7 | 3015115350206155 |
oct | 321554215423343 |
9 | 56020880721121 |
10 | 14411262994147 |
11 | 4656867294208 |
12 | 1748bba999917 |
13 | 806c8cb2b966 |
14 | 37b71a400ad5 |
15 | 19ed0b4d51b7 |
hex | d1b623626e3 |
14411262994147 has 2 divisors, whose sum is σ = 14411262994148. Its totient is φ = 14411262994146.
The previous prime is 14411262994127. The next prime is 14411262994153. The reversal of 14411262994147 is 74149926211441.
14411262994147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14411262994147 - 215 = 14411262961379 is a prime.
It is not a weakly prime, because it can be changed into another prime (14411262994127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205631497073 + 7205631497074.
It is an arithmetic number, because the mean of its divisors is an integer number (7205631497074).
Almost surely, 214411262994147 is an apocalyptic number.
14411262994147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14411262994147 is an equidigital number, since it uses as much as digits as its factorization.
14411262994147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3483648, while the sum is 55.
The spelling of 14411262994147 in words is "fourteen trillion, four hundred eleven billion, two hundred sixty-two million, nine hundred ninety-four thousand, one hundred forty-seven".
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