14411331103341 has 4 divisors (see below), whose sum is σ = 19215108137792. Its totient is φ = 9607554068892.

The previous prime is 14411331103339. The next prime is 14411331103361. The reversal of 14411331103341 is 14330113311441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14411331103341 - 2¹ = 14411331103339 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14411331103299 and 14411331103308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14411331103321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2401888517221 + ... + 2401888517226.

It is an arithmetic number, because the mean of its divisors is an integer number (4803777034448).

Almost surely, 2^{14411331103341} is an apocalyptic number.

It is an amenable number.

14411331103341 is a deficient number, since it is larger than the sum of its proper divisors (4803777034451).

14411331103341 is an equidigital number, since it uses as much as digits as its factorization.

14411331103341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4803777034450.

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 14411331103341 its reverse (14330113311441), we get a palindrome (28741444414782).

The spelling of 14411331103341 in words is "fourteen trillion, four hundred eleven billion, three hundred thirty-one million, one hundred three thousand, three hundred forty-one".