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1441201403 is a prime number
BaseRepresentation
bin101010111100110…
…1111110011111011
310201102212121122202
41111321233303323
510422421421103
6355001540415
750500003235
oct12571576373
93642777582
101441201403
1167a57aa44
123427a470b
1319c7760c5
14d9599255
15867d2988
hex55e6fcfb

1441201403 has 2 divisors, whose sum is σ = 1441201404. Its totient is φ = 1441201402.

The previous prime is 1441201327. The next prime is 1441201417. The reversal of 1441201403 is 3041021441.

It is a strong prime.

It is an emirp because it is prime and its reverse (3041021441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1441201403 - 226 = 1374092539 is a prime.

It is a super-2 number, since 2×14412014032 = 4154122968018336818, which contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1441201103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720600701 + 720600702.

It is an arithmetic number, because the mean of its divisors is an integer number (720600702).

Almost surely, 21441201403 is an apocalyptic number.

1441201403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1441201403 is an equidigital number, since it uses as much as digits as its factorization.

1441201403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 1441201403 is about 37963.1584960999. The cubic root of 1441201403 is about 1129.5571927798.

Adding to 1441201403 its reverse (3041021441), we get a palindrome (4482222844).

The spelling of 1441201403 in words is "one billion, four hundred forty-one million, two hundred one thousand, four hundred three".