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1441210131281 is a prime number
BaseRepresentation
bin10100111110001110110…
…100010110001101010001
312002210000102010101000102
4110332032310112031101
5142103044243200111
63022025514502145
7206060346663254
oct24761664261521
95083012111012
101441210131281
11506239601928
121b3396434955
13a5ba05ba13b
144da7d7c309b
1527750ed413b
hex14f8ed16351

1441210131281 has 2 divisors, whose sum is σ = 1441210131282. Its totient is φ = 1441210131280.

The previous prime is 1441210131239. The next prime is 1441210131287. The reversal of 1441210131281 is 1821310121441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 825744777025 + 615465354256 = 908705^2 + 784516^2 .

It is a cyclic number.

It is not a de Polignac number, because 1441210131281 - 210 = 1441210130257 is a prime.

It is a super-2 number, since 2×14412101312812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1441210131287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720605065640 + 720605065641.

It is an arithmetic number, because the mean of its divisors is an integer number (720605065641).

Almost surely, 21441210131281 is an apocalyptic number.

It is an amenable number.

1441210131281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1441210131281 is an equidigital number, since it uses as much as digits as its factorization.

1441210131281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 29.

The spelling of 1441210131281 in words is "one trillion, four hundred forty-one billion, two hundred ten million, one hundred thirty-one thousand, two hundred eighty-one".