144121433 has 2 divisors, whose sum is σ = 144121434. Its totient is φ = 144121432.

The previous prime is 144121357. The next prime is 144121459. The reversal of 144121433 is 334121441.

144121433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114233344 + 29888089 = 10688^2 + 5467^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-144121433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144121399 and 144121408.

It is not a weakly prime, because it can be changed into another prime (144121463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72060716 + 72060717.

It is an arithmetic number, because the mean of its divisors is an integer number (72060717).

Almost surely, 2^144121433 is an apocalyptic number.

It is an amenable number.

144121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

144121433 is an equidigital number, since it uses as much as digits as its factorization.

144121433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 23.

The square root of 144121433 is about 12005.0586420892. The cubic root of 144121433 is about 524.2955728578.

Adding to 144121433 its reverse (334121441), we get a palindrome (478242874).

The spelling of 144121433 in words is "one hundred forty-four million, one hundred twenty-one thousand, four hundred thirty-three".