Base | Representation |
---|---|
bin | 10100111110010000000… |
… | …100000000000010110011 |
3 | 12002210001212102020000002 |
4 | 110332100010000002303 |
5 | 142103120114341034 |
6 | 3022031542220215 |
7 | 206061022321121 |
oct | 24762004000263 |
9 | 5083055366002 |
10 | 1441231012019 |
11 | 50624a373937 |
12 | 1b33a142466b |
13 | a5ba4a1b3c6 |
14 | 4da8249a911 |
15 | 27752c5ae7e |
hex | 14f901000b3 |
1441231012019 has 2 divisors, whose sum is σ = 1441231012020. Its totient is φ = 1441231012018.
The previous prime is 1441231012003. The next prime is 1441231012097. The reversal of 1441231012019 is 9102101321441.
It is a weak prime.
It is an emirp because it is prime and its reverse (9102101321441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1441231012019 - 24 = 1441231012003 is a prime.
It is a super-2 number, since 2×14412310120192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1441231011982 and 1441231012000.
It is not a weakly prime, because it can be changed into another prime (1441231012519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720615506009 + 720615506010.
It is an arithmetic number, because the mean of its divisors is an integer number (720615506010).
Almost surely, 21441231012019 is an apocalyptic number.
1441231012019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1441231012019 is an equidigital number, since it uses as much as digits as its factorization.
1441231012019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 1441231012019 in words is "one trillion, four hundred forty-one billion, two hundred thirty-one million, twelve thousand, nineteen".
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