Base | Representation |
---|---|
bin | 10100111110010000001… |
… | …011110000001010100011 |
3 | 12002210002000020110112111 |
4 | 110332100023300022203 |
5 | 142103121124403011 |
6 | 3022032053540151 |
7 | 206061045513466 |
oct | 24762013601243 |
9 | 5083060213474 |
10 | 1441233044131 |
11 | 506250531671 |
12 | 1b33a2044657 |
13 | a5ba528033a |
14 | 4da828692dd |
15 | 2775300d121 |
hex | 14f902f02a3 |
1441233044131 has 2 divisors, whose sum is σ = 1441233044132. Its totient is φ = 1441233044130.
The previous prime is 1441233044107. The next prime is 1441233044161. The reversal of 1441233044131 is 1314403321441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1441233044131 - 231 = 1439085560483 is a prime.
It is a super-2 number, since 2×14412330441312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1441233044093 and 1441233044102.
It is not a weakly prime, because it can be changed into another prime (1441233044161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720616522065 + 720616522066.
It is an arithmetic number, because the mean of its divisors is an integer number (720616522066).
Almost surely, 21441233044131 is an apocalyptic number.
1441233044131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1441233044131 is an equidigital number, since it uses as much as digits as its factorization.
1441233044131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1441233044131 its reverse (1314403321441), we get a palindrome (2755636365572).
The spelling of 1441233044131 in words is "one trillion, four hundred forty-one billion, two hundred thirty-three million, forty-four thousand, one hundred thirty-one".
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