14412405212131 has 2 divisors, whose sum is σ = 14412405212132. Its totient is φ = 14412405212130.

The previous prime is 14412405212077. The next prime is 14412405212167. The reversal of 14412405212131 is 13121250421441.

14412405212131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14412405212131 - 2²³ = 14412396823523 is a prime.

It is a super-2 number, since 2×14412405212131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14412405212093 and 14412405212102.

It is not a weakly prime, because it can be changed into another prime (14412405212431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206202606065 + 7206202606066.

It is an arithmetic number, because the mean of its divisors is an integer number (7206202606066).

Almost surely, 2^{14412405212131} is an apocalyptic number.

14412405212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14412405212131 is an equidigital number, since it uses as much as digits as its factorization.

14412405212131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 14412405212131 its reverse (13121250421441), we get a palindrome (27533655633572).

The spelling of 14412405212131 in words is "fourteen trillion, four hundred twelve billion, four hundred five million, two hundred twelve thousand, one hundred thirty-one".