Base | Representation |
---|---|
bin | 100000110001010010001110… |
… | …111101101001100110000011 |
3 | 200220022011001202001000010211 |
4 | 200301102032331221212003 |
5 | 122342313102201013103 |
6 | 1230305444333534551 |
7 | 42233432014223134 |
oct | 4061221675514603 |
9 | 626264052030124 |
10 | 144124321110403 |
11 | 41a16865a54157 |
12 | 141b8313644457 |
13 | 6255b329c464a |
14 | 27839237d3c8b |
15 | 119e00e9a136d |
hex | 83148ef69983 |
144124321110403 has 2 divisors, whose sum is σ = 144124321110404. Its totient is φ = 144124321110402.
The previous prime is 144124321110389. The next prime is 144124321110433. The reversal of 144124321110403 is 304011123421441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144124321110403 - 213 = 144124321102211 is a prime.
It is a super-3 number, since 3×1441243211104033 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (144124321110433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72062160555201 + 72062160555202.
It is an arithmetic number, because the mean of its divisors is an integer number (72062160555202).
Almost surely, 2144124321110403 is an apocalyptic number.
144124321110403 is a deficient number, since it is larger than the sum of its proper divisors (1).
144124321110403 is an equidigital number, since it uses as much as digits as its factorization.
144124321110403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 144124321110403 its reverse (304011123421441), we get a palindrome (448135444531844).
The spelling of 144124321110403 in words is "one hundred forty-four trillion, one hundred twenty-four billion, three hundred twenty-one million, one hundred ten thousand, four hundred three".
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