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14413201034114 = 27206600517057
BaseRepresentation
bin1101000110111101010110…
…1110100100101110000010
31220000212222202120100011202
43101233111232210232002
53342121213431042424
650353155543141202
73015214362241361
oct321572556445602
956025882510152
1014413201034114
114657671261333
12174945ba44802
1380720b4c0b7c
1437b86196b7d8
1519edc17092ae
hexd1bd5ba4b82

14413201034114 has 4 divisors (see below), whose sum is σ = 21619801551174. Its totient is φ = 7206600517056.

The previous prime is 14413201034107. The next prime is 14413201034207. The reversal of 14413201034114 is 41143010231441.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13799850484225 + 613350549889 = 3714815^2 + 783167^2 .

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3603300258527 + ... + 3603300258530.

Almost surely, 214413201034114 is an apocalyptic number.

14413201034114 is a deficient number, since it is larger than the sum of its proper divisors (7206600517060).

14413201034114 is an equidigital number, since it uses as much as digits as its factorization.

14413201034114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7206600517059.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 14413201034114 its reverse (41143010231441), we get a palindrome (55556211265555).

The spelling of 14413201034114 in words is "fourteen trillion, four hundred thirteen billion, two hundred one million, thirty-four thousand, one hundred fourteen".

Divisors: 1 2 7206600517057 14413201034114