Base | Representation |
---|---|
bin | 1101000110111101010111… |
… | …0110100110110110100010 |
3 | 1220000212222220112022220121 |
4 | 3101233111312212312202 |
5 | 3342121220000440002 |
6 | 50353200100230454 |
7 | 3015214416162112 |
oct | 321572566466642 |
9 | 56025886468817 |
10 | 14413203140002 |
11 | 465767246a537 |
12 | 174946069b42a |
13 | 80720ba7a564 |
14 | 37b861d59042 |
15 | 19edc19c3237 |
hex | d1bd5da6da2 |
14413203140002 has 4 divisors (see below), whose sum is σ = 21619804710006. Its totient is φ = 7206601570000.
The previous prime is 14413203139997. The next prime is 14413203140009. The reversal of 14413203140002 is 20004130231441.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12764549708001 + 1648653432001 = 3572751^2 + 1283999^2 .
It is not an unprimeable number, because it can be changed into a prime (14413203140009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3603300784999 + ... + 3603300785002.
Almost surely, 214413203140002 is an apocalyptic number.
14413203140002 is a deficient number, since it is larger than the sum of its proper divisors (7206601570004).
14413203140002 is an equidigital number, since it uses as much as digits as its factorization.
14413203140002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7206601570003.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14413203140002 its reverse (20004130231441), we get a palindrome (34417333371443).
The spelling of 14413203140002 in words is "fourteen trillion, four hundred thirteen billion, two hundred three million, one hundred forty thousand, two".
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