1441344054113 has 2 divisors, whose sum is σ = 1441344054114. Its totient is φ = 1441344054112.

The previous prime is 1441344054091. The next prime is 1441344054127. The reversal of 1441344054113 is 3114504431441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1280806002529 + 160538051584 = 1131727^2 + 400672^2 .

It is a cyclic number.

It is not a de Polignac number, because 1441344054113 - 2²⁰ = 1441343005537 is a prime.

It is not a weakly prime, because it can be changed into another prime (1441344054013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720672027056 + 720672027057.

It is an arithmetic number, because the mean of its divisors is an integer number (720672027057).

Almost surely, 2^{1441344054113} is an apocalyptic number.

It is an amenable number.

1441344054113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1441344054113 is an equidigital number, since it uses as much as digits as its factorization.

1441344054113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 1441344054113 its reverse (3114504431441), we get a palindrome (4555848485554).

The spelling of 1441344054113 in words is "one trillion, four hundred forty-one billion, three hundred forty-four million, fifty-four thousand, one hundred thirteen".