14414153251441 has 2 divisors, whose sum is σ = 14414153251442. Its totient is φ = 14414153251440.

The previous prime is 14414153251361. The next prime is 14414153251471. The reversal of 14414153251441 is 14415235141441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14366533283041 + 47619968400 = 3790321^2 + 218220^2 .

It is an emirp because it is prime and its reverse (14415235141441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14414153251441 - 2¹⁹ = 14414152727153 is a prime.

It is a super-3 number, since 3×14414153251441³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14414153251394 and 14414153251403.

It is not a weakly prime, because it can be changed into another prime (14414153251471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7207076625720 + 7207076625721.

It is an arithmetic number, because the mean of its divisors is an integer number (7207076625721).

Almost surely, 2^{14414153251441} is an apocalyptic number.

It is an amenable number.

14414153251441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14414153251441 is an equidigital number, since it uses as much as digits as its factorization.

14414153251441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 153600, while the sum is 40.

Adding to 14414153251441 its reverse (14415235141441), we get a palindrome (28829388392882).

The spelling of 14414153251441 in words is "fourteen trillion, four hundred fourteen billion, one hundred fifty-three million, two hundred fifty-one thousand, four hundred forty-one".