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14420175143 = 111310925013
BaseRepresentation
bin11010110111000001…
…00110100100100111
31101012222002210111212
431123200212210213
5214013031101033
610342522222035
71020226315643
oct153340464447
941188083455
1014420175143
11612a8a4020
12296535491b
13148a69551a
149ab20dc23
15595e7e748
hex35b826927

14420175143 has 4 divisors (see below), whose sum is σ = 15731100168. Its totient is φ = 13109250120.

The previous prime is 14420175079. The next prime is 14420175257. The reversal of 14420175143 is 34157102441.

14420175143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14420175143 - 26 = 14420175079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14420175043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655462496 + ... + 655462517.

It is an arithmetic number, because the mean of its divisors is an integer number (3932775042).

Almost surely, 214420175143 is an apocalyptic number.

14420175143 is a deficient number, since it is larger than the sum of its proper divisors (1310925025).

14420175143 is a wasteful number, since it uses less digits than its factorization.

14420175143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1310925024.

The product of its (nonzero) digits is 13440, while the sum is 32.

Adding to 14420175143 its reverse (34157102441), we get a palindrome (48577277584).

The spelling of 14420175143 in words is "fourteen billion, four hundred twenty million, one hundred seventy-five thousand, one hundred forty-three".

Divisors: 1 11 1310925013 14420175143