1442113333 has 4 divisors (see below), whose sum is σ = 1448147520. Its totient is φ = 1436079148.

The previous prime is 1442113307. The next prime is 1442113429. The reversal of 1442113333 is 3333112441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3333112441 = 2503 ⋅1331647.

It is a cyclic number.

It is not a de Polignac number, because 1442113333 - 2⁵ = 1442113301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1442113298 and 1442113307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1442113033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3016735 + ... + 3017212.

It is an arithmetic number, because the mean of its divisors is an integer number (362036880).

Almost surely, 2^1442113333 is an apocalyptic number.

It is an amenable number.

1442113333 is a deficient number, since it is larger than the sum of its proper divisors (6034187).

1442113333 is an equidigital number, since it uses as much as digits as its factorization.

1442113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6034186.

The product of its digits is 2592, while the sum is 25.

The square root of 1442113333 is about 37975.1673202370. The cubic root of 1442113333 is about 1129.7953875485.

Adding to 1442113333 its reverse (3333112441), we get a palindrome (4775225774).

The spelling of 1442113333 in words is "one billion, four hundred forty-two million, one hundred thirteen thousand, three hundred thirty-three".