Base | Representation |
---|---|
bin | 1101000111011011100110… |
… | …1110101000100100000011 |
3 | 1220001122221200010122102011 |
4 | 3101312321232220210003 |
5 | 3342234331213104103 |
6 | 50401021415033351 |
7 | 3015622532555614 |
oct | 321667156504403 |
9 | 56048850118364 |
10 | 14421321222403 |
11 | 4660058959a47 |
12 | 174ab4736b857 |
13 | 807c038c5804 |
14 | 37bdd219dc0b |
15 | 1a01e9545d6d |
hex | d1db9ba8903 |
14421321222403 has 2 divisors, whose sum is σ = 14421321222404. Its totient is φ = 14421321222402.
The previous prime is 14421321222361. The next prime is 14421321222433. The reversal of 14421321222403 is 30422212312441.
14421321222403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14421321222403 - 225 = 14421287667971 is a prime.
It is not a weakly prime, because it can be changed into another prime (14421321222433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210660611201 + 7210660611202.
It is an arithmetic number, because the mean of its divisors is an integer number (7210660611202).
Almost surely, 214421321222403 is an apocalyptic number.
14421321222403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14421321222403 is an equidigital number, since it uses as much as digits as its factorization.
14421321222403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14421321222403 its reverse (30422212312441), we get a palindrome (44843533534844).
The spelling of 14421321222403 in words is "fourteen trillion, four hundred twenty-one billion, three hundred twenty-one million, two hundred twenty-two thousand, four hundred three".
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