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14421341003 is a prime number
BaseRepresentation
bin11010110111001010…
…00011001101001011
31101020001022000202212
431123211003031023
5214013330403003
610343003215335
71020242242646
oct153345031513
941201260685
1014421341003
11613051aa43
12296581754b
13148a9b3094
149ab434a5d
1559610edd8
hex35b94334b

14421341003 has 2 divisors, whose sum is σ = 14421341004. Its totient is φ = 14421341002.

The previous prime is 14421340963. The next prime is 14421341027. The reversal of 14421341003 is 30014312441.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14421341003 - 222 = 14417146699 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14421341003.

It is not a weakly prime, because it can be changed into another prime (14421341083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210670501 + 7210670502.

It is an arithmetic number, because the mean of its divisors is an integer number (7210670502).

Almost surely, 214421341003 is an apocalyptic number.

14421341003 is a deficient number, since it is larger than the sum of its proper divisors (1).

14421341003 is an equidigital number, since it uses as much as digits as its factorization.

14421341003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14421341003 its reverse (30014312441), we get a palindrome (44435653444).

The spelling of 14421341003 in words is "fourteen billion, four hundred twenty-one million, three hundred forty-one thousand, three".