Base | Representation |
---|---|
bin | 100000110010100101010100… |
… | …111101100111000111100011 |
3 | 200220121200100201111211011202 |
4 | 200302211110331213013203 |
5 | 122400243313314204242 |
6 | 1230414441534231415 |
7 | 42243041006142251 |
oct | 4062452475470743 |
9 | 626550321454152 |
10 | 144213542334947 |
11 | 41a50690010768 |
12 | 1421167365556b |
13 | 6261381385637 |
14 | 2787d890cd5d1 |
15 | 11a14d2799932 |
hex | 832954f671e3 |
144213542334947 has 2 divisors, whose sum is σ = 144213542334948. Its totient is φ = 144213542334946.
The previous prime is 144213542334941. The next prime is 144213542335021. The reversal of 144213542334947 is 749433245312441.
144213542334947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144213542334947 - 24 = 144213542334931 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 144213542334892 and 144213542334901.
It is not a weakly prime, because it can be changed into another prime (144213542334941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72106771167473 + 72106771167474.
It is an arithmetic number, because the mean of its divisors is an integer number (72106771167474).
Almost surely, 2144213542334947 is an apocalyptic number.
144213542334947 is a deficient number, since it is larger than the sum of its proper divisors (1).
144213542334947 is an equidigital number, since it uses as much as digits as its factorization.
144213542334947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34836480, while the sum is 56.
The spelling of 144213542334947 in words is "one hundred forty-four trillion, two hundred thirteen billion, five hundred forty-two million, three hundred thirty-four thousand, nine hundred forty-seven".
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