Base | Representation |
---|---|
bin | 100000110010100101111000… |
… | …010011011011000111111111 |
3 | 200220121201220001012022100010 |
4 | 200302211320103123013333 |
5 | 122400301022111134201 |
6 | 1230415020434434303 |
7 | 42243061465654614 |
oct | 4062457023330777 |
9 | 626551801168303 |
10 | 144214135255551 |
11 | 41a50964773799 |
12 | 142117ba132993 |
13 | 6261447172b2a |
14 | 2788003b5250b |
15 | 11a1519869bd6 |
hex | 8329784db1ff |
144214135255551 has 32 divisors (see below), whose sum is σ = 202481085864960. Its totient is φ = 91048740322176.
The previous prime is 144214135255523. The next prime is 144214135255571. The reversal of 144214135255551 is 155552531412441.
It is not a de Polignac number, because 144214135255551 - 245 = 109029763166719 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 144214135255551.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144214135255571) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2345410330 + ... + 2345471816.
It is an arithmetic number, because the mean of its divisors is an integer number (6327533933280).
Almost surely, 2144214135255551 is an apocalyptic number.
144214135255551 is a deficient number, since it is larger than the sum of its proper divisors (58266950609409).
144214135255551 is a wasteful number, since it uses less digits than its factorization.
144214135255551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76143.
The product of its digits is 2400000, while the sum is 48.
Adding to 144214135255551 its reverse (155552531412441), we get a palindrome (299766666667992).
The spelling of 144214135255551 in words is "one hundred forty-four trillion, two hundred fourteen billion, one hundred thirty-five million, two hundred fifty-five thousand, five hundred fifty-one".
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