Base | Representation |
---|---|
bin | 1000011001001111010… |
… | …1111001010111011001 |
3 | 111210020112122111200212 |
4 | 2012103311321113121 |
5 | 4330322330100441 |
6 | 150130124540505 |
7 | 13263523216403 |
oct | 2062365712731 |
9 | 453215574625 |
10 | 144214300121 |
11 | 56185238201 |
12 | 23b490b1735 |
13 | 107a3a068c8 |
14 | 6da1207b73 |
15 | 3b40bc7eeb |
hex | 2193d795d9 |
144214300121 has 2 divisors, whose sum is σ = 144214300122. Its totient is φ = 144214300120.
The previous prime is 144214300117. The next prime is 144214300127. The reversal of 144214300121 is 121003412441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 141572340121 + 2641960000 = 376261^2 + 51400^2 .
It is a cyclic number.
It is not a de Polignac number, because 144214300121 - 22 = 144214300117 is a prime.
It is a super-2 number, since 2×1442143001212 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (144214300127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72107150060 + 72107150061.
It is an arithmetic number, because the mean of its divisors is an integer number (72107150061).
Almost surely, 2144214300121 is an apocalyptic number.
It is an amenable number.
144214300121 is a deficient number, since it is larger than the sum of its proper divisors (1).
144214300121 is an equidigital number, since it uses as much as digits as its factorization.
144214300121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 144214300121 its reverse (121003412441), we get a palindrome (265217712562).
The spelling of 144214300121 in words is "one hundred forty-four billion, two hundred fourteen million, three hundred thousand, one hundred twenty-one".
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