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144214300121 is a prime number
BaseRepresentation
bin1000011001001111010…
…1111001010111011001
3111210020112122111200212
42012103311321113121
54330322330100441
6150130124540505
713263523216403
oct2062365712731
9453215574625
10144214300121
1156185238201
1223b490b1735
13107a3a068c8
146da1207b73
153b40bc7eeb
hex2193d795d9

144214300121 has 2 divisors, whose sum is σ = 144214300122. Its totient is φ = 144214300120.

The previous prime is 144214300117. The next prime is 144214300127. The reversal of 144214300121 is 121003412441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 141572340121 + 2641960000 = 376261^2 + 51400^2 .

It is a cyclic number.

It is not a de Polignac number, because 144214300121 - 22 = 144214300117 is a prime.

It is a super-2 number, since 2×1442143001212 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144214300127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72107150060 + 72107150061.

It is an arithmetic number, because the mean of its divisors is an integer number (72107150061).

Almost surely, 2144214300121 is an apocalyptic number.

It is an amenable number.

144214300121 is a deficient number, since it is larger than the sum of its proper divisors (1).

144214300121 is an equidigital number, since it uses as much as digits as its factorization.

144214300121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 144214300121 its reverse (121003412441), we get a palindrome (265217712562).

The spelling of 144214300121 in words is "one hundred forty-four billion, two hundred fourteen million, three hundred thousand, one hundred twenty-one".