Base | Representation |
---|---|
bin | 11010110111011111… |
… | …00101010011110011 |
3 | 1101020020111022022212 |
4 | 31123233211103303 |
5 | 214020032232011 |
6 | 10343142322335 |
7 | 1020304562615 |
oct | 153357452363 |
9 | 41206438285 |
10 | 14424102131 |
11 | 613203646a |
12 | 29667293ab |
13 | 148b43ba9a |
14 | 9ab952db5 |
15 | 5964a808b |
hex | 35bbe54f3 |
14424102131 has 2 divisors, whose sum is σ = 14424102132. Its totient is φ = 14424102130.
The previous prime is 14424102067. The next prime is 14424102137. The reversal of 14424102131 is 13120142441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14424102131 - 26 = 14424102067 is a prime.
It is a super-2 number, since 2×144241021312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14424102097 and 14424102106.
It is not a weakly prime, because it can be changed into another prime (14424102137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7212051065 + 7212051066.
It is an arithmetic number, because the mean of its divisors is an integer number (7212051066).
Almost surely, 214424102131 is an apocalyptic number.
14424102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14424102131 is an equidigital number, since it uses as much as digits as its factorization.
14424102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14424102131 its reverse (13120142441), we get a palindrome (27544244572).
The spelling of 14424102131 in words is "fourteen billion, four hundred twenty-four million, one hundred two thousand, one hundred thirty-one".
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