Base | Representation |
---|---|
bin | 1101000111100111111001… |
… | …0110111100101000111011 |
3 | 1220001222110120121020122212 |
4 | 3101321332112330220323 |
5 | 3342313110222442411 |
6 | 50402325022005335 |
7 | 3016100351016635 |
oct | 321717626745073 |
9 | 56058416536585 |
10 | 14424620124731 |
11 | 46614a1014103 |
12 | 174b70811684b |
13 | 80830b1b231b |
14 | 37c226371a55 |
15 | 1a033de7d68b |
hex | d1e7e5bca3b |
14424620124731 has 2 divisors, whose sum is σ = 14424620124732. Its totient is φ = 14424620124730.
The previous prime is 14424620124709. The next prime is 14424620124749. The reversal of 14424620124731 is 13742102642441.
It is a strong prime.
It is an emirp because it is prime and its reverse (13742102642441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14424620124731 - 226 = 14424553015867 is a prime.
It is a super-2 number, since 2×144246201247312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14424620124781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7212310062365 + 7212310062366.
It is an arithmetic number, because the mean of its divisors is an integer number (7212310062366).
Almost surely, 214424620124731 is an apocalyptic number.
14424620124731 is a deficient number, since it is larger than the sum of its proper divisors (1).
14424620124731 is an equidigital number, since it uses as much as digits as its factorization.
14424620124731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 258048, while the sum is 41.
The spelling of 14424620124731 in words is "fourteen trillion, four hundred twenty-four billion, six hundred twenty million, one hundred twenty-four thousand, seven hundred thirty-one".
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