Base | Representation |
---|---|
bin | 100000110011110101111110… |
… | …101010000111011100000011 |
3 | 200220220221212221120122200222 |
4 | 200303311332222013130003 |
5 | 122403203142122312233 |
6 | 1230522323020533255 |
7 | 42252225006360545 |
oct | 4063657652073403 |
9 | 626827787518628 |
10 | 144300141213443 |
11 | 41a843898aa936 |
12 | 142264013b122b |
13 | 62695a267b487 |
14 | 278c24240b695 |
15 | 11a38a024b898 |
hex | 833d7ea87703 |
144300141213443 has 2 divisors, whose sum is σ = 144300141213444. Its totient is φ = 144300141213442.
The previous prime is 144300141213383. The next prime is 144300141213491. The reversal of 144300141213443 is 344312141003441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144300141213443 - 228 = 144299872777987 is a prime.
It is not a weakly prime, because it can be changed into another prime (144300141213143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72150070606721 + 72150070606722.
It is an arithmetic number, because the mean of its divisors is an integer number (72150070606722).
Almost surely, 2144300141213443 is an apocalyptic number.
144300141213443 is a deficient number, since it is larger than the sum of its proper divisors (1).
144300141213443 is an equidigital number, since it uses as much as digits as its factorization.
144300141213443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 144300141213443 its reverse (344312141003441), we get a palindrome (488612282216884).
The spelling of 144300141213443 in words is "one hundred forty-four trillion, three hundred billion, one hundred forty-one million, two hundred thirteen thousand, four hundred forty-three".
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