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144300425143 = 753388949933
BaseRepresentation
bin1000011001100011111…
…0011011111110110111
3111210110112201010000111
42012120332123332313
54331011402101033
6150142442523451
713265620242640
oct2063076337667
9453415633014
10144300425143
1156219912206
1223b71b06587
13107b87ccb64
146dac8266c7
153b4853b7cd
hex2198f9bfb7

144300425143 has 8 divisors (see below), whose sum is σ = 168026371488. Its totient is φ = 121352378784.

The previous prime is 144300425131. The next prime is 144300425147. The reversal of 144300425143 is 341524003441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 144300425143 - 25 = 144300425111 is a prime.

It is a super-2 number, since 2×1443004251432 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144300425147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 194474596 + ... + 194475337.

It is an arithmetic number, because the mean of its divisors is an integer number (21003296436).

Almost surely, 2144300425143 is an apocalyptic number.

144300425143 is a deficient number, since it is larger than the sum of its proper divisors (23725946345).

144300425143 is an equidigital number, since it uses as much as digits as its factorization.

144300425143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 388949993.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 144300425143 its reverse (341524003441), we get a palindrome (485824428584).

The spelling of 144300425143 in words is "one hundred forty-four billion, three hundred million, four hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 7 53 371 388949933 2722649531 20614346449 144300425143