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1443031312049 is a prime number
BaseRepresentation
bin10100111111111011010…
…111100110011010110001
312002221201022222221100222
4110333323113212122301
5142120312003441144
63022530333022425
7206153442525215
oct24777327463261
95087638887328
101443031312049
11506a936129a8
121b3804324a15
13a61009b4bb2
144dbb3610945
152780ad232ee
hex14ffb5e66b1

1443031312049 has 2 divisors, whose sum is σ = 1443031312050. Its totient is φ = 1443031312048.

The previous prime is 1443031312013. The next prime is 1443031312087. The reversal of 1443031312049 is 9402131303441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1101282336400 + 341748975649 = 1049420^2 + 584593^2 .

It is an emirp because it is prime and its reverse (9402131303441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1443031312049 is a prime.

It is not a weakly prime, because it can be changed into another prime (1443031312649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721515656024 + 721515656025.

It is an arithmetic number, because the mean of its divisors is an integer number (721515656025).

Almost surely, 21443031312049 is an apocalyptic number.

It is an amenable number.

1443031312049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1443031312049 is an equidigital number, since it uses as much as digits as its factorization.

1443031312049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 1443031312049 in words is "one trillion, four hundred forty-three billion, thirty-one million, three hundred twelve thousand, forty-nine".