Base | Representation |
---|---|
bin | 10101000000000010000… |
… | …010001010000101000001 |
3 | 12002222000010101221202112 |
4 | 111000002002022011001 |
5 | 142121024120201312 |
6 | 3022545405425105 |
7 | 206156301135266 |
oct | 25000202120501 |
9 | 5088003357675 |
10 | 1443143131457 |
11 | 507040747535 |
12 | 1b383586b195 |
13 | a611ac06421 |
14 | 4dbc43db26d |
15 | 27815a5ed22 |
hex | 1500208a141 |
1443143131457 has 2 divisors, whose sum is σ = 1443143131458. Its totient is φ = 1443143131456.
The previous prime is 1443143131427. The next prime is 1443143131481. The reversal of 1443143131457 is 7541313413441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1315611294001 + 127531837456 = 1147001^2 + 357116^2 .
It is a cyclic number.
It is not a de Polignac number, because 1443143131457 - 26 = 1443143131393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1443143131427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721571565728 + 721571565729.
It is an arithmetic number, because the mean of its divisors is an integer number (721571565729).
Almost surely, 21443143131457 is an apocalyptic number.
It is an amenable number.
1443143131457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1443143131457 is an equidigital number, since it uses as much as digits as its factorization.
1443143131457 is an evil number, because the sum of its binary digits is even.
The product of its digits is 241920, while the sum is 41.
Adding to 1443143131457 its reverse (7541313413441), we get a palindrome (8984456544898).
The spelling of 1443143131457 in words is "one trillion, four hundred forty-three billion, one hundred forty-three million, one hundred thirty-one thousand, four hundred fifty-seven".
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