Search a number
-
+
14433121169 is a prime number
BaseRepresentation
bin11010111000100011…
…11111001110010001
31101020212110112010022
431130101333032101
5214024334334134
610344103513225
71020444335315
oct153421771621
941225415108
1014433121169
116137136615
122969758815
131490278cac
149acc1db45
1559718a52e
hex35c47f391

14433121169 has 2 divisors, whose sum is σ = 14433121170. Its totient is φ = 14433121168.

The previous prime is 14433121141. The next prime is 14433121177. The reversal of 14433121169 is 96112133441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10728816400 + 3704304769 = 103580^2 + 60863^2 .

It is a cyclic number.

It is not a de Polignac number, because 14433121169 - 212 = 14433117073 is a prime.

It is a super-2 number, since 2×144331211692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14433121139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216560584 + 7216560585.

It is an arithmetic number, because the mean of its divisors is an integer number (7216560585).

Almost surely, 214433121169 is an apocalyptic number.

It is an amenable number.

14433121169 is a deficient number, since it is larger than the sum of its proper divisors (1).

14433121169 is an equidigital number, since it uses as much as digits as its factorization.

14433121169 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 35.

The spelling of 14433121169 in words is "fourteen billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred sixty-nine".