Base | Representation |
---|---|
bin | 11010111000101000… |
… | …01100100011110001 |
3 | 1101020220112221020111 |
4 | 31130110030203301 |
5 | 214030011400311 |
6 | 10344124141321 |
7 | 1020452266153 |
oct | 153424144361 |
9 | 41226487214 |
10 | 14433700081 |
11 | 61374a1559 |
12 | 2969997841 |
13 | 149041c648 |
14 | 9acd30ad3 |
15 | 597251d21 |
hex | 35c50c8f1 |
14433700081 has 2 divisors, whose sum is σ = 14433700082. Its totient is φ = 14433700080.
The previous prime is 14433700069. The next prime is 14433700139. The reversal of 14433700081 is 18000733441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14332878400 + 100821681 = 119720^2 + 10041^2 .
It is a cyclic number.
It is not a de Polignac number, because 14433700081 - 213 = 14433691889 is a prime.
It is a super-2 number, since 2×144337000812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14233700081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216850040 + 7216850041.
It is an arithmetic number, because the mean of its divisors is an integer number (7216850041).
Almost surely, 214433700081 is an apocalyptic number.
It is an amenable number.
14433700081 is a deficient number, since it is larger than the sum of its proper divisors (1).
14433700081 is an equidigital number, since it uses as much as digits as its factorization.
14433700081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
The spelling of 14433700081 in words is "fourteen billion, four hundred thirty-three million, seven hundred thousand, eighty-one".
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