Base | Representation |
---|---|
bin | 1101001000001100011010… |
… | …0011111011110011110011 |
3 | 1220002220202122110210201201 |
4 | 3102003012203323303303 |
5 | 3342443143341021342 |
6 | 50411025345512031 |
7 | 3016565263463362 |
oct | 322030643736363 |
9 | 56086678423651 |
10 | 14434421423347 |
11 | 46656706528a2 |
12 | 17515a2642617 |
13 | 80921097b5c3 |
14 | 37c8b5d6d7d9 |
15 | 1a071468bdb7 |
hex | d20c68fbcf3 |
14434421423347 has 2 divisors, whose sum is σ = 14434421423348. Its totient is φ = 14434421423346.
The previous prime is 14434421423293. The next prime is 14434421423377. The reversal of 14434421423347 is 74332412443441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14434421423347 - 215 = 14434421390579 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14434421423297 and 14434421423306.
It is not a weakly prime, because it can be changed into another prime (14434421423377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217210711673 + 7217210711674.
It is an arithmetic number, because the mean of its divisors is an integer number (7217210711674).
Almost surely, 214434421423347 is an apocalyptic number.
14434421423347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14434421423347 is an equidigital number, since it uses as much as digits as its factorization.
14434421423347 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3096576, while the sum is 46.
Adding to 14434421423347 its reverse (74332412443441), we get a palindrome (88766833866788).
The spelling of 14434421423347 in words is "fourteen trillion, four hundred thirty-four billion, four hundred twenty-one million, four hundred twenty-three thousand, three hundred forty-seven".
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