Base | Representation |
---|---|
bin | 100000110100101111000101… |
… | …000000100010001100001011 |
3 | 200221010211010201211102012111 |
4 | 200310233011000202030023 |
5 | 122410204222431144301 |
6 | 1231010422435123151 |
7 | 42256525222313254 |
oct | 4064570500421413 |
9 | 627124121742174 |
10 | 144361451037451 |
11 | 41aa839068507a |
12 | 14236271a434b7 |
13 | 62722c35a304b |
14 | 27911bac1bb2b |
15 | 11a528c980551 |
hex | 834bc502230b |
144361451037451 has 2 divisors, whose sum is σ = 144361451037452. Its totient is φ = 144361451037450.
The previous prime is 144361451037443. The next prime is 144361451037533. The reversal of 144361451037451 is 154730154163441.
It is a weak prime.
It is an emirp because it is prime and its reverse (154730154163441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 144361451037451 - 23 = 144361451037443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 144361451037395 and 144361451037404.
It is not a weakly prime, because it can be changed into another prime (144361451037421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72180725518725 + 72180725518726.
It is an arithmetic number, because the mean of its divisors is an integer number (72180725518726).
Almost surely, 2144361451037451 is an apocalyptic number.
144361451037451 is a deficient number, since it is larger than the sum of its proper divisors (1).
144361451037451 is an equidigital number, since it uses as much as digits as its factorization.
144361451037451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 49.
The spelling of 144361451037451 in words is "one hundred forty-four trillion, three hundred sixty-one billion, four hundred fifty-one million, thirty-seven thousand, four hundred fifty-one".
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