Base | Representation |
---|---|
bin | 11010111001011010… |
… | …10100101011100011 |
3 | 1101021100221120201111 |
4 | 31130231110223203 |
5 | 214033203140242 |
6 | 10344521244151 |
7 | 1020562261642 |
oct | 153455245343 |
9 | 41240846644 |
10 | 14440286947 |
11 | 6140190349 |
12 | 2970033657 |
13 | 14918b77b8 |
14 | 9adb67359 |
15 | 597b03817 |
hex | 35cb54ae3 |
14440286947 has 2 divisors, whose sum is σ = 14440286948. Its totient is φ = 14440286946.
The previous prime is 14440286929. The next prime is 14440286951. The reversal of 14440286947 is 74968204441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14440286947 is a prime.
It is a super-3 number, since 3×144402869473 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 14440286947.
It is not a weakly prime, because it can be changed into another prime (14440286447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7220143473 + 7220143474.
It is an arithmetic number, because the mean of its divisors is an integer number (7220143474).
Almost surely, 214440286947 is an apocalyptic number.
14440286947 is a deficient number, since it is larger than the sum of its proper divisors (1).
14440286947 is an equidigital number, since it uses as much as digits as its factorization.
14440286947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1548288, while the sum is 49.
The spelling of 14440286947 in words is "fourteen billion, four hundred forty million, two hundred eighty-six thousand, nine hundred forty-seven".
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