1444130314441 has 4 divisors (see below), whose sum is σ = 1474856491392. Its totient is φ = 1413404137492.

The previous prime is 1444130314433. The next prime is 1444130314447.

1444130314441 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1444130314441 - 2³ = 1444130314433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1444130314397 and 1444130314406.

It is not an unprimeable number, because it can be changed into a prime (1444130314447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15363088405 + ... + 15363088498.

It is an arithmetic number, because the mean of its divisors is an integer number (368714122848).

Almost surely, 2^{1444130314441} is an apocalyptic number.

It is an amenable number.

1444130314441 is a deficient number, since it is larger than the sum of its proper divisors (30726176951).

1444130314441 is an equidigital number, since it uses as much as digits as its factorization.

1444130314441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30726176950.

The product of its (nonzero) digits is 36864, while the sum is 34.

It can be divided in two parts, 1444130 and 314441, that added together give a palindrome (1758571).

The spelling of 1444130314441 in words is "one trillion, four hundred forty-four billion, one hundred thirty million, three hundred fourteen thousand, four hundred forty-one".