14442332130111 has 4 divisors (see below), whose sum is σ = 19256442840152. Its totient is φ = 9628221420072.

The previous prime is 14442332130013. The next prime is 14442332130151. The reversal of 14442332130111 is 11103123324441.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14442332130111 - 2¹⁵ = 14442332097343 is a prime.

It is a super-3 number, since 3×14442332130111³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14442332130151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2407055355016 + ... + 2407055355021.

It is an arithmetic number, because the mean of its divisors is an integer number (4814110710038).

Almost surely, 2^{14442332130111} is an apocalyptic number.

14442332130111 is a deficient number, since it is larger than the sum of its proper divisors (4814110710041).

14442332130111 is an equidigital number, since it uses as much as digits as its factorization.

14442332130111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4814110710040.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 14442332130111 its reverse (11103123324441), we get a palindrome (25545455454552).

The spelling of 14442332130111 in words is "fourteen trillion, four hundred forty-two billion, three hundred thirty-two million, one hundred thirty thousand, one hundred eleven".