Base | Representation |
---|---|
bin | 11010111001110000… |
… | …01011111001001011 |
3 | 1101021120022020212212 |
4 | 31130320023321023 |
5 | 214034420301124 |
6 | 10345102255335 |
7 | 1020625421651 |
oct | 153470137113 |
9 | 41246266785 |
10 | 14443134539 |
11 | 6141855829 |
12 | 2970b8754b |
13 | 1492373972 |
14 | 9b02a8dd1 |
15 | 597eb740e |
hex | 35ce0be4b |
14443134539 has 2 divisors, whose sum is σ = 14443134540. Its totient is φ = 14443134538.
The previous prime is 14443134523. The next prime is 14443134583. The reversal of 14443134539 is 93543134441.
It is a weak prime.
It is an emirp because it is prime and its reverse (93543134441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14443134539 - 24 = 14443134523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14443134496 and 14443134505.
It is not a weakly prime, because it can be changed into another prime (14443133539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7221567269 + 7221567270.
It is an arithmetic number, because the mean of its divisors is an integer number (7221567270).
Almost surely, 214443134539 is an apocalyptic number.
14443134539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14443134539 is an equidigital number, since it uses as much as digits as its factorization.
14443134539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 311040, while the sum is 41.
The spelling of 14443134539 in words is "fourteen billion, four hundred forty-three million, one hundred thirty-four thousand, five hundred thirty-nine".
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