Base | Representation |
---|---|
bin | 10101000001001101000… |
… | …110000010011111000100 |
3 | 12010002020220000110111120 |
4 | 111001031012002133010 |
5 | 142131114011041012 |
6 | 3023314353033540 |
7 | 206232432111201 |
oct | 25011506023704 |
9 | 5102226013446 |
10 | 1444402440132 |
11 | 507627581803 |
12 | 1b3b275558b0 |
13 | a628ba94ca2 |
14 | 4dca3768ca8 |
15 | 2788b3b358c |
hex | 1504d1827c4 |
1444402440132 has 24 divisors (see below), whose sum is σ = 3370331511456. Its totient is φ = 481459029888.
The previous prime is 1444402440073. The next prime is 1444402440133. The reversal of 1444402440132 is 2310442044441.
It is a junction number, because it is equal to n+sod(n) for n = 1444402440093 and 1444402440102.
It is not an unprimeable number, because it can be changed into a prime (1444402440133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 323733 + ... + 1730204.
It is an arithmetic number, because the mean of its divisors is an integer number (140430479644).
Almost surely, 21444402440132 is an apocalyptic number.
1444402440132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1444402440132 is an abundant number, since it is smaller than the sum of its proper divisors (1925929071324).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1444402440132 is a wasteful number, since it uses less digits than its factorization.
1444402440132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2112547 (or 2112545 counting only the distinct ones).
The product of its (nonzero) digits is 49152, while the sum is 33.
Adding to 1444402440132 its reverse (2310442044441), we get a palindrome (3754844484573).
The spelling of 1444402440132 in words is "one trillion, four hundred forty-four billion, four hundred two million, four hundred forty thousand, one hundred thirty-two".
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