Base | Representation |
---|---|
bin | 110111000110… |
… | …011001010001 |
3 | 1000011211121011 |
4 | 313012121101 |
5 | 12144202423 |
6 | 1233330521 |
7 | 233526055 |
oct | 67063121 |
9 | 30154534 |
10 | 14444113 |
11 | 8176092 |
12 | 4a06a41 |
13 | 2cb9618 |
14 | 1cbdc65 |
15 | 1404b0d |
hex | dc6651 |
14444113 has 2 divisors, whose sum is σ = 14444114. Its totient is φ = 14444112.
The previous prime is 14444107. The next prime is 14444137. The reversal of 14444113 is 31144441.
14444113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8573184 + 5870929 = 2928^2 + 2423^2 .
It is an emirp because it is prime and its reverse (31144441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14444113 - 25 = 14444081 is a prime.
It is a nialpdrome in base 16.
It is not a weakly prime, because it can be changed into another prime (14444153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222056 + 7222057.
It is an arithmetic number, because the mean of its divisors is an integer number (7222057).
Almost surely, 214444113 is an apocalyptic number.
It is an amenable number.
14444113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14444113 is an equidigital number, since it uses as much as digits as its factorization.
14444113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 768, while the sum is 22.
The square root of 14444113 is about 3800.5411456791. The cubic root of 14444113 is about 243.5362563668.
Adding to 14444113 its reverse (31144441), we get a palindrome (45588554).
The spelling of 14444113 in words is "fourteen million, four hundred forty-four thousand, one hundred thirteen".
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