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14444251344331 is a prime number
BaseRepresentation
bin1101001000110001000001…
…1110000110110111001011
31220010212010201012112022021
43102030100132012313023
53343123311321004311
650415333015105311
73020364004440214
oct322142036066713
956125121175267
1014444251344331
114669855360a36
121753486672237
1380a1193597b3
1437d16969c40b
151a0adc651171
hexd2310786dcb

14444251344331 has 2 divisors, whose sum is σ = 14444251344332. Its totient is φ = 14444251344330.

The previous prime is 14444251344287. The next prime is 14444251344473. The reversal of 14444251344331 is 13344315244441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14444251344331 - 27 = 14444251344203 is a prime.

It is a super-2 number, since 2×144442513443312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14444251374331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222125672165 + 7222125672166.

It is an arithmetic number, because the mean of its divisors is an integer number (7222125672166).

Almost surely, 214444251344331 is an apocalyptic number.

14444251344331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14444251344331 is an equidigital number, since it uses as much as digits as its factorization.

14444251344331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1105920, while the sum is 43.

Adding to 14444251344331 its reverse (13344315244441), we get a palindrome (27788566588772).

The spelling of 14444251344331 in words is "fourteen trillion, four hundred forty-four billion, two hundred fifty-one million, three hundred forty-four thousand, three hundred thirty-one".