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14444425113233 is a prime number
BaseRepresentation
bin1101001000110001101011…
…0100111110111010010001
31220010212120211011220102112
43102030122310332322101
53343124140312110413
650415402143355105
73020401214444123
oct322143264767221
956125524156375
1014444425113233
1146699344580a5
1217535148b2a95
1380a14635b42b
1437d1847b3213
151a0aeca282a8
hexd231ad3ee91

14444425113233 has 2 divisors, whose sum is σ = 14444425113234. Its totient is φ = 14444425113232.

The previous prime is 14444425113221. The next prime is 14444425113269. The reversal of 14444425113233 is 33231152444441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13065745227649 + 1378679885584 = 3614657^2 + 1174172^2 .

It is a cyclic number.

It is not a de Polignac number, because 14444425113233 - 210 = 14444425112209 is a prime.

It is not a weakly prime, because it can be changed into another prime (14444425113203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222212556616 + 7222212556617.

It is an arithmetic number, because the mean of its divisors is an integer number (7222212556617).

Almost surely, 214444425113233 is an apocalyptic number.

It is an amenable number.

14444425113233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14444425113233 is an equidigital number, since it uses as much as digits as its factorization.

14444425113233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 552960, while the sum is 41.

Adding to 14444425113233 its reverse (33231152444441), we get a palindrome (47675577557674).

The spelling of 14444425113233 in words is "fourteen trillion, four hundred forty-four billion, four hundred twenty-five million, one hundred thirteen thousand, two hundred thirty-three".