Base | Representation |
---|---|
bin | 11010111001111010… |
… | …01011010111011111 |
3 | 1101021122202201220012 |
4 | 31130331023113133 |
5 | 214040234134403 |
6 | 10345150313435 |
7 | 1020642512006 |
oct | 153475132737 |
9 | 41248681805 |
10 | 14444443103 |
11 | 6142569992 |
12 | 29714b887b |
13 | 149271146c |
14 | 9b0529c3d |
15 | 598174ed8 |
hex | 35cf4b5df |
14444443103 has 4 divisors (see below), whose sum is σ = 14477802528. Its totient is φ = 14411083680.
The previous prime is 14444443081. The next prime is 14444443109. The reversal of 14444443103 is 30134444441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14444443103 - 212 = 14444439007 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14444443103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14444443109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16679063 + ... + 16679928.
It is an arithmetic number, because the mean of its divisors is an integer number (3619450632).
Almost surely, 214444443103 is an apocalyptic number.
14444443103 is a deficient number, since it is larger than the sum of its proper divisors (33359425).
14444443103 is an equidigital number, since it uses as much as digits as its factorization.
14444443103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33359424.
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 14444443103 its reverse (30134444441), we get a palindrome (44578887544).
The spelling of 14444443103 in words is "fourteen billion, four hundred forty-four million, four hundred forty-three thousand, one hundred three".
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