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144445310425243 is a prime number
BaseRepresentation
bin100000110101111101001011…
…011010101101100010011011
3200221102211121001001200222001
4200311331023122231202123
5122413042443432101433
61231113132020541431
742265554306331312
oct4065751332554233
9627384531050861
10144445310425243
114202aa04065343
121424a576251877
13627a199166679
142795294387279
1511a7549b9b57d
hex835f4b6ad89b

144445310425243 has 2 divisors, whose sum is σ = 144445310425244. Its totient is φ = 144445310425242.

The previous prime is 144445310425177. The next prime is 144445310425259. The reversal of 144445310425243 is 342524013544441.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144445310425243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144445310425193 and 144445310425202.

It is not a weakly prime, because it can be changed into another prime (144445310425543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72222655212621 + 72222655212622.

It is an arithmetic number, because the mean of its divisors is an integer number (72222655212622).

Almost surely, 2144445310425243 is an apocalyptic number.

144445310425243 is a deficient number, since it is larger than the sum of its proper divisors (1).

144445310425243 is an equidigital number, since it uses as much as digits as its factorization.

144445310425243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3686400, while the sum is 46.

Adding to 144445310425243 its reverse (342524013544441), we get a palindrome (486969323969684).

The spelling of 144445310425243 in words is "one hundred forty-four trillion, four hundred forty-five billion, three hundred ten million, four hundred twenty-five thousand, two hundred forty-three".