Base | Representation |
---|---|
bin | 1101001000110010000101… |
… | …0000100011000000001111 |
3 | 1220010212212100012020100020 |
4 | 3102030201100203000033 |
5 | 3343124400422033010 |
6 | 50415421000033223 |
7 | 3020403664464306 |
oct | 322144120430017 |
9 | 56125770166306 |
10 | 14444533002255 |
11 | 466998a347784 |
12 | 1753544a62813 |
13 | 80a1628049a5 |
14 | 37d194c5943d |
15 | 1a0b0723a470 |
hex | d232142300f |
14444533002255 has 64 divisors (see below), whose sum is σ = 23306386493952. Its totient is φ = 7638943334400.
The previous prime is 14444533002247. The next prime is 14444533002259. The reversal of 14444533002255 is 55220033544441.
It is not a de Polignac number, because 14444533002255 - 23 = 14444533002247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14444533002259) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2634418744 + ... + 2634424226.
It is an arithmetic number, because the mean of its divisors is an integer number (364162288968).
Almost surely, 214444533002255 is an apocalyptic number.
14444533002255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14444533002255 is a deficient number, since it is larger than the sum of its proper divisors (8861853491697).
14444533002255 is a wasteful number, since it uses less digits than its factorization.
14444533002255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7928.
The product of its (nonzero) digits is 1152000, while the sum is 42.
Adding to 14444533002255 its reverse (55220033544441), we get a palindrome (69664566546696).
The spelling of 14444533002255 in words is "fourteen trillion, four hundred forty-four billion, five hundred thirty-three million, two thousand, two hundred fifty-five".
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