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14445112459993 is a prime number
BaseRepresentation
bin1101001000110100001111…
…0011000000001011011001
31220010221100201112201220221
43102031003303000023121
53343132042242204433
650415554255520041
73020424232005415
oct322150363001331
956127321481827
1014445112459993
11466a157444976
121753686b29021
1380a22588a3a7
1437d20bbb5d45
151a0b3d04b72d
hexd2343cc02d9

14445112459993 has 2 divisors, whose sum is σ = 14445112459994. Its totient is φ = 14445112459992.

The previous prime is 14445112459957. The next prime is 14445112460039. The reversal of 14445112459993 is 39995421154441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12715592887449 + 1729519572544 = 3565893^2 + 1315112^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14445112459993 is a prime.

It is a super-2 number, since 2×144451124599932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14445112489993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222556229996 + 7222556229997.

It is an arithmetic number, because the mean of its divisors is an integer number (7222556229997).

Almost surely, 214445112459993 is an apocalyptic number.

It is an amenable number.

14445112459993 is a deficient number, since it is larger than the sum of its proper divisors (1).

14445112459993 is an equidigital number, since it uses as much as digits as its factorization.

14445112459993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 27993600, while the sum is 61.

The spelling of 14445112459993 in words is "fourteen trillion, four hundred forty-five billion, one hundred twelve million, four hundred fifty-nine thousand, nine hundred ninety-three".